[Missing <summary> documentation for "M:VVVV.Utils.Streams.StreamUtils.AssignFrom``1(VVVV.Utils.Streams.IOutStream{``0},VVVV.Utils.Streams.IInStream{``0})"]

Namespace: VVVV.Utils.Streams
Assembly: VVVV.Utils (in VVVV.Utils.dll) Version: 1.0.4694.10871

Syntax

C#
public static void AssignFrom<T>(
	this IOutStream<T> outStream,
	IInStream<T> inStream
)

Parameters

outStream
Type: VVVV.Utils.Streams..::..IOutStream<(Of <(<'T>)>)>

[Missing <param name="outStream"/> documentation for "M:VVVV.Utils.Streams.StreamUtils.AssignFrom``1(VVVV.Utils.Streams.IOutStream{``0},VVVV.Utils.Streams.IInStream{``0})"]

inStream
Type: VVVV.Utils.Streams..::..IInStream<(Of <(<'T>)>)>

[Missing <param name="inStream"/> documentation for "M:VVVV.Utils.Streams.StreamUtils.AssignFrom``1(VVVV.Utils.Streams.IOutStream{``0},VVVV.Utils.Streams.IInStream{``0})"]

Type Parameters

T

[Missing <typeparam name="T"/> documentation for "M:VVVV.Utils.Streams.StreamUtils.AssignFrom``1(VVVV.Utils.Streams.IOutStream{``0},VVVV.Utils.Streams.IInStream{``0})"]

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IOutStream<(Of <(<'T>)>)>. When you use instance method syntax to call this method, omit the first parameter. For more information, see or .

See Also